Nilai lim_(x→2)⁡(x^2-5x+6)/(x^2-4)=⋯

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Bahas Soal Matematika   »   Limit   ›  

Nilai \( \displaystyle \lim_{x \to 2} \ \frac{x^2-5x+6}{x^2-4} = \cdots \)

  1. \( -\frac{1}{4} \)
  2. \( -\frac{1}{8} \)
  3. \( -\frac{1}{8} \)
  4. \( 1 \)
  5. \( \frac{5}{4} \)

(EBTANAS SMA IPA 2002)

Pembahasan:

\begin{aligned} \lim_{x \to 2} \ \frac{x^2-5x+6}{x^2-4} &= \lim_{x \to 2} \ \frac{(x-2)(x-3)}{(x-2)(x+2)} \\[8pt] &= \lim_{x \to 2} \ \frac{(x-3)}{(x+2)} \\[8pt] &= \frac{2-3}{2+2} = -\frac{1}{4} \end{aligned}

Jawaban A.